Prove that,if a positive integer is of the fo | vedclass

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(A) Given that the positive integer is of the form $6m + 5$,where $m$ is an integer.We can rewrite the expression $6m + 5$ as $6m + 3 + 2$.Factoring o

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(A) Given that the positive integer is of the form $6m + 5$,where $m$ is an integer.We can rewrite the expression $6m + 5$ as $6m + 3 + 2$.Factoring out $3$ from the first two terms,we get $3(2m + 1) + 2$.Let $n = 2m + 1$. Since $m$ is an integer,$n$ is also an integer.Substituting $n$ into the expression,we get $3n + 2$.Thus,any integer of the form $6m + 5$ can be expressed in the form $3n + 2$.

Prove that,if a positive integer is of the form $6m + 5$,then it is also of the form $3n + 2$ for some integer $n$.

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