Radioactive C^{14} is incorporated into CO_2 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In $C_3$ plants,the first step of the Calvin cycle is the carboxylation of $RuBP$ (Ribulose$-1,5-$bisphosphate).During this process,$CO_2$ is fixe

Vedclass · Accepted Answer

$PGA$

Vedclass · Answer

(D) In $C_3$ plants,the first step of the Calvin cycle is the carboxylation of $RuBP$ (Ribulose$-1,5-$bisphosphate).During this process,$CO_2$ is fixed by the enzyme $RuBisCO$ to form a $6$-carbon unstable intermediate.This unstable intermediate immediately breaks down into two molecules of $3$-phosphoglyceric acid $(PGA)$.Since the radioactive $C^{14}$ is part of the $CO_2$ molecule,it will first appear in the stable $3$-carbon compound,which is $PGA$.

Radioactive $C^{14}$ is incorporated into $CO_2$ and released into the atmosphere. This $CO_2$ is taken up by $RuBP$ in a $C_3$ plant. In which compound is the radioactive $C^{14}$ first detected?

Similar Questions

Which enzyme is the most abundant protein in the whole biosphere?

In $C_3$ plants,the first stable product of photosynthesis during dark reaction is

Regeneration of four molecules of $RuBP$ in $C_3$ cycle requires the expenditure of . . . . . . $ATP$.

Melvin Calvin used ....... to separate the various chemicals formed during the Calvin cycle.

In Calvin cycle,if one molecule of $RuBP$ is carboxylated then how many $PGA$ molecules will be formed?

Vedclass Test Series

Exam Paper Generator

Online Exam Module