(A) The stability of a nucleus depends on its $n/p$ ratio. Isotopes with an excessive $n/p$ ratio (too many neutrons) are unstable and tend to undergo

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(A) The stability of a nucleus depends on its $n/p$ ratio. Isotopes with an excessive $n/p$ ratio (too many neutrons) are unstable and tend to undergo $\beta^-$ decay to convert a neutron into a proton,thereby decreasing the $n/p$ ratio. This process involves the emission of an electron $(e^-)$.

Class 12 Chemistry Nuclear Chemistry Nucleus (Stability and Reaction)

Medium

Radioactive isotopes that have an excessive neutron/proton ratio generally exhibit

A
$e^-$ emission
B
$_{2}He^{4}$ emission
C
$e^+$ emission
D
$K$ electron capture

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Nuclear Chemistry

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Nucleus (Stability and Reaction)

${}_{90}Th^{232} \rightarrow {}_{82}Pb^{208}$. The number of $\alpha$ and $\beta$-particles emitted during the above reaction is:

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The hydrogen bomb is based on the phenomenon of:

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The energy required to separate a neutron and a proton from the nucleus is called:

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The activity of a radioisotope changes with:

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If two light nuclei are fused together in a nuclear fusion reaction,what happens to the average binding energy per nucleon?

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Radioactive isotopes that have an excessive neutron/proton ratio generally exhibit

Similar Questions

${}_{90}Th^{232} \rightarrow {}_{82}Pb^{208}$. The number of $\alpha$ and $\beta$-particles emitted during the above reaction is:

The hydrogen bomb is based on the phenomenon of:

The energy required to separate a neutron and a proton from the nucleus is called:

The activity of a radioisotope changes with:

If two light nuclei are fused together in a nuclear fusion reaction,what happens to the average binding energy per nucleon?

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