Rasheed got a playing top (lattu) as his birt | vedclass

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(A) The total surface area to be coloured is the sum of the curved surface area of the hemisphere and the curved surface area of the cone.Given:Diamet

Vedclass · Accepted Answer

$39.6$

Vedclass · Answer

(A) The total surface area to be coloured is the sum of the curved surface area of the hemisphere and the curved surface area of the cone.Given:Diameter of the top $= 3.5 \, cm$Radius $(r) = \frac{3.5}{2} = 1.75 \, cm$Total height of the top $= 5 \, cm$Height of the cone $(h) = 	ext{Total height} - 	ext{Radius of hemisphere} = 5 - 1.75 = 3.25 \, cm$Slant height of the cone $(l) = \sqrt{r^2 + h^2} = \sqrt{(1.75)^2 + (3.25)^2} = \sqrt{3.0625 + 10.5625} = \sqrt{13.625} \approx 3.69 \, cm \approx 3.7 \, cm$Curved surface area of hemisphere $= 2 \pi r^2 = 2 	imes \frac{22}{7} 	imes 1.75 	imes 1.75 = 19.25 \, cm^2$Curved surface area of cone $= \pi r l = \frac{22}{7} 	imes 1.75 	imes 3.7 = 20.35 \, cm^2$Total area to be coloured $= 19.25 + 20.35 = 39.6 \, cm^2$.

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