Rate law for the reaction,$C_2H_5I_{(g)} \rightarrow C_2H_{4_{(g)}} + HI_{(g)}$ is $r = k[C_2H_5I]$. What is the order and molecularity of this reaction?
- Aorder and molecularity both are $1$
- Border is $1$ and molecularity is $2$
- Corder and molecularity both are $2$
- Dorder is $2$ and molecularity is $1$
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For the reaction $A + B \rightarrow \text{product}$,the rate of reaction is $3.6 \times 10^{-2} \ mol \ dm^{-3} \ sec^{-1}$. When $[A] = 0.2 \ mol \ dm^{-3}$ and $[B] = 0.1 \ mol \ dm^{-3}$,calculate the rate constant of the reaction if the reaction is first order in $A$ and second order in $B$.
The reaction $A_2 + B_2 \rightarrow 2AB$ follows the mechanism $A_2 \underset{k_{-1}}{\stackrel{k_1}{\rightleftharpoons}} 2A$ (fast),$A + B_2 \xrightarrow{k_2} AB + B$ (slow),$A + B \rightarrow AB$ (fast). The overall order of the reaction is:
In the reaction sequence $A$ $\xrightarrow{K_1} B$ $\xrightarrow{K_2} C$ $\xrightarrow{K_3} D$,where $K_3 > K_2 > K_1$,which step determines the rate of the reaction?
Easy
View SolutionFor the non-stoichiometric reaction $2A + B \rightarrow C + D,$ the following kinetic data were obtained in three separate experiments,all at $298 \, K.$
Initial Concentration $(A)$ Initial Concentration $(B)$ Initial rate of formation of $C$ $(mol \, L^{-1} \, s^{-1})$ $0.1 \, M$ $0.1 \, M$ $1.2 \times 10^{-3}$ $0.1 \, M$ $0.2 \, M$ $1.2 \times 10^{-3}$ $0.2 \, M$ $0.1 \, M$ $2.4 \times 10^{-3}$
The rate law for the formation of $C$ is:
| Initial Concentration $(A)$ | Initial Concentration $(B)$ | Initial rate of formation of $C$ $(mol \, L^{-1} \, s^{-1})$ |
| $0.1 \, M$ | $0.1 \, M$ | $1.2 \times 10^{-3}$ |
| $0.1 \, M$ | $0.2 \, M$ | $1.2 \times 10^{-3}$ |
| $0.2 \, M$ | $0.1 \, M$ | $2.4 \times 10^{-3}$ |
The rate law for the formation of $C$ is:
DifficultJEE MAIN 2014
View SolutionIn a multistep reaction,the overall rate of reaction is equal to the
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