Rate law for the reaction $aA + bB \rightarrow cC + dD$ is $r = k[A][B]$. Which of the following conditions does $NOT$ affect the rate of reaction?
- AConcentration of $A$ is doubled and concentration of $B$ is kept constant.
- BConcentration of $B$ is doubled and concentration of $A$ is kept constant.
- CConcentration of $B$ is doubled and concentration of $A$ is halved.
- DConcentration of $A$ is kept constant and concentration of $B$ is halved.
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For a reaction $2 \ A + B \rightarrow P$, when the concentration of $B$ alone is doubled, the rate does not change, and when the concentrations of both $A$ and $B$ are doubled, the rate increases by a factor of $4$. The unit of the rate constant is,
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View SolutionFor the reaction $A + B \rightarrow \text{Product}$,the order with respect to $A$ is $1$ and with respect to $B$ is $1/2$. When the concentrations of both $A$ and $B$ are increased by a factor of $4$,the rate of reaction increases by a factor of .......
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View SolutionConsider the kinetic data given in the following table for the reaction $A + B + C \rightarrow$ Product.
Experiment No.
$[A] \ (mol \ dm^{-3})$
$[B] \ (mol \ dm^{-3})$
$[C] \ (mol \ dm^{-3})$
Rate of reaction $(mol \ dm^{-3} \ s^{-1})$
$1$
$0.2$
$0.1$
$0.1$
$6.0 \times 10^{-5}$
$2$
$0.2$
$0.2$
$0.1$
$6.0 \times 10^{-5}$
$3$
$0.2$
$0.1$
$0.2$
$1.2 \times 10^{-4}$
$4$
$0.3$
$0.1$
$0.1$
$9.0 \times 10^{-5}$
The rate of the reaction for $[A]=0.15 \ mol \ dm^{-3}, [B]=0.25 \ mol \ dm^{-3}$ and $[C]=0.15 \ mol \ dm^{-3}$ is found to be $Y \times 10^{-5} \ mol \ dm^{-3} \ s^{-1}$. The value of $Y$ is . . . . . .
| Experiment No. | $[A] \ (mol \ dm^{-3})$ | $[B] \ (mol \ dm^{-3})$ | $[C] \ (mol \ dm^{-3})$ | Rate of reaction $(mol \ dm^{-3} \ s^{-1})$ |
| $1$ | $0.2$ | $0.1$ | $0.1$ | $6.0 \times 10^{-5}$ |
| $2$ | $0.2$ | $0.2$ | $0.1$ | $6.0 \times 10^{-5}$ |
| $3$ | $0.2$ | $0.1$ | $0.2$ | $1.2 \times 10^{-4}$ |
| $4$ | $0.3$ | $0.1$ | $0.1$ | $9.0 \times 10^{-5}$ |
The rate of the reaction for $[A]=0.15 \ mol \ dm^{-3}, [B]=0.25 \ mol \ dm^{-3}$ and $[C]=0.15 \ mol \ dm^{-3}$ is found to be $Y \times 10^{-5} \ mol \ dm^{-3} \ s^{-1}$. The value of $Y$ is . . . . . .
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