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(C) The given reaction is a nucleophilic aromatic substitution reaction $(S_NAr)$.Nucleophilic substitution on an aromatic ring is facilitated by the

Vedclass · Accepted Answer

$-NO_2$

Vedclass · Answer

(C) The given reaction is a nucleophilic aromatic substitution reaction $(S_NAr)$.Nucleophilic substitution on an aromatic ring is facilitated by the presence of strong electron-withdrawing groups (EWGs) at the ortho or para positions.These groups reduce the electron density of the aromatic ring,making it more susceptible to attack by a nucleophile (like $OH^-$ from $NaOH$).Among the given options,$-NO_2$ is a strong electron-withdrawing group due to its $-I$ and $-M$ effects.$-OCH_3$ and $-CH_3$ are electron-donating groups,which decrease the rate of nucleophilic substitution.Therefore,the rate of reaction is maximum when $G = -NO_2$.

The rate of reaction is maximum if $G$ is:

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