The ratio of C_p and C_v of a gas X is 1.4. T | vedclass

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Question

(A) The ratio of heat capacities $\frac{C_p}{C_v} = 1.4$ indicates that the gas $X$ is diatomic.At $NTP$,$22.4 \ L$ of any gas contains $1 \ mol$ of m

Vedclass · Accepted Answer

$6.02 	imes 10^{23}$

Vedclass · Answer

(A) The ratio of heat capacities $\frac{C_p}{C_v} = 1.4$ indicates that the gas $X$ is diatomic.At $NTP$,$22.4 \ L$ of any gas contains $1 \ mol$ of molecules.Therefore,$11.2 \ L$ of gas $X$ corresponds to $\frac{11.2}{22.4} = 0.5 \ mol$ of molecules.Number of molecules $= 0.5 	imes 6.022 	imes 10^{23} = 3.011 	imes 10^{23}$ molecules.Since the gas is diatomic,each molecule contains $2$ atoms.Number of atoms $= 2 	imes 3.011 	imes 10^{23} = 6.022 	imes 10^{23}$ atoms.

The ratio of $C_p$ and $C_v$ of a gas $X$ is $1.4$. The number of atoms of the gas $X$ present in $11.2 \ L$ of it at $NTP$ will be:

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