The ratio of $C_p$ and $C_v$ of a gas $'X'$ is $1.4$. The number of atoms of the gas $'X'$ present in $11.2 \ L$ of it at $NTP$ will be:
- A$6.02 \times 10^{23}$
- B$1.2 \times 10^{23}$
- C$3.01 \times 10^{23}$
- D$2.01 \times 10^{23}$
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