The ratio of the energy of a photon with wave | vedclass

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(B) The energy of a photon is given by the formula $E = \frac{hc}{\lambda}$.Since $h$ and $c$ are constants,the energy $E$ is inversely proportional t

Vedclass · Accepted Answer

$2 : 1$

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(B) The energy of a photon is given by the formula $E = \frac{hc}{\lambda}$.Since $h$ and $c$ are constants,the energy $E$ is inversely proportional to the wavelength $\lambda$,i.e.,$E \propto \frac{1}{\lambda}$.Therefore,the ratio of energies is $\frac{E_1}{E_2} = \frac{\lambda_2}{\lambda_1}$.Given $\lambda_1 = 3000 \ \mathring{A}$ and $\lambda_2 = 6000 \ \mathring{A}$.Substituting the values,we get $\frac{E_1}{E_2} = \frac{6000}{3000} = \frac{2}{1}$.Thus,the ratio is $2 : 1$.

The ratio of the energy of a photon with wavelength $3000 \ \mathring{A}$ to that of a photon with wavelength $6000 \ \mathring{A}$ is:

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