Reactant A of the above reaction is(A) + begi | vedclass

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Question

(B) The reaction involves the cyclization of ethylene glycol with phosgene $(COCl_2)$ in the presence of pyridine.Ethylene glycol acts as a nucleophil

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$COCl_2$

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(B) The reaction involves the cyclization of ethylene glycol with phosgene $(COCl_2)$ in the presence of pyridine.Ethylene glycol acts as a nucleophile,attacking the electrophilic carbonyl carbon of phosgene.Pyridine acts as a base to neutralize the $HCl$ produced during the reaction.The reaction proceeds as follows:$HO-CH_2-CH_2-OH + COCl_2 \xrightarrow{	ext{Pyridine}} 	ext{Cyclic carbonate} + 2HCl$.Thus,reactant $A$ is phosgene $(COCl_2)$.

$I. HNO_3$	$II. NH_2NH_2 / OH^-$
$III. 2[Ag(NH_3)_2]^+$	$IV. NaOH$

Reactant $A$ of the above reaction is
$(A)$ + $\begin{matrix} CH_2-OH \\ | \\ CH_2-OH \end{matrix}$ $\xrightarrow{\text{Pyridine}} \begin{matrix} CH_2-O \\ | \\ CH_2-O \end{matrix} > C = O$

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Reactant $A$ of the above reaction is$(A)$ + $\begin{matrix} CH_2-OH \\ | \\ CH_2-OH \end{matrix}$ $\xrightarrow{\text{Pyridine}} \begin{matrix} CH_2-O \\ | \\ CH_2-O \end{matrix} > C = O$