Reactant of Column-$I$ when reacted with acetaldehyde in the presence of $H^{+}$ gives the product given in Column-$II$ and their names are given in Column-$III$. Match the reactants in Column-$I$ with the products in Column-$II$ and their names in Column-$III$.
Column-$I$ (Reagent) Column-$II$ (Product) and Column-$III$ (Name)
$A$. Ammonia $(NH_{3})$ $i$. $CH_{3}CH=NCH_{3}$; $m$. Acetaldehyde hydrazone
$B$. Amine $(CH_{3}NH_{2})$ $ii$. $CH_{3}CH=NNH_{2}$; $n$. Acetaldehyde oxime
$C$. Hydroxyl amine $(NH_{2}OH)$ $iii$. $CH_{3}CH=NH$; $o$. Acetaldehyde imine
$D$. Hydrazine $(NH_{2}NH_{2})$ $iv$. $CH_{3}CH=NOH$; $q$. Acetaldehyde methyl imine

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(A) The reaction of acetaldehyde $(CH_{3}CHO)$ with ammonia derivatives in the presence of $H^{+}$ follows the general reaction: $CH_{3}CHO + H_{2}N-Z \rightarrow CH_{3}CH=N-Z + H_{2}O$.
$A$. Ammonia $(NH_{3})$ reacts to form $CH_{3}CH=NH$ (Acetaldehyde imine) $\rightarrow A-iii-o$.
$B$. Methylamine $(CH_{3}NH_{2})$ reacts to form $CH_{3}CH=NCH_{3}$ (Acetaldehyde methyl imine) $\rightarrow B-i-q$.
$C$. Hydroxylamine $(NH_{2}OH)$ reacts to form $CH_{3}CH=NOH$ (Acetaldehyde oxime) $\rightarrow C-iv-n$.
$D$. Hydrazine $(NH_{2}NH_{2})$ reacts to form $CH_{3}CH=NNH_{2}$ (Acetaldehyde hydrazone) $\rightarrow D-ii-m$.
Correct matching: $A-iii-o, B-i-q, C-iv-n, D-ii-m$.

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