Reaction A_{(g)} rightarrow 2B_{(g)} + C_{(g) | vedclass

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(C) For the reaction $A_{(g)} \rightarrow 2B_{(g)} + C_{(g)}$:At $t=0$,$P_A = P_0$ and $P_{total} = P_0$.At $t=\infty$,all $A$ is consumed,so $P_{\inf

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Rate constant of the reaction is $1.693 \ min^{-1}$

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(C) For the reaction $A_{(g)} ightarrow 2B_{(g)} + C_{(g)}$:At $t=0$,$P_A = P_0$ and $P_{total} = P_0$.At $t=\infty$,all $A$ is consumed,so $P_{\infty} = 2P_0 + P_0 = 3P_0 = 240 \ mm \ Hg$,which gives $P_0 = 80 \ mm \ Hg$. Thus,option $(a)$ is correct.At $t=10 \ min$,$P_{total} = (P_0 - x) + 2x + x = P_0 + 2x = 160 \ mm \ Hg$.Substituting $P_0 = 80$,we get $80 + 2x = 160$,so $x = 40 \ mm \ Hg$.Partial pressure of $A$ at $10 \ min = P_0 - x = 80 - 40 = 40 \ mm \ Hg$. Thus,option $(d)$ is correct.Rate constant $k = \frac{2.303}{t} \log \frac{P_0}{P_A} = \frac{2.303}{10} \log \frac{80}{40} = \frac{2.303 	imes 0.3010}{10} = 0.0693 \ min^{-1}$. Thus,option $(c)$ is incorrect.First order reactions theoretically never go to completion,so option $(b)$ is correct.

$t/min$	Pressure of system at time $t/mm \ Hg$
$10$	$160$
$\infty$	$240$

Reaction $A_{(g)} \rightarrow 2B_{(g)} + C_{(g)}$ is a first order reaction. It was started with pure $A$.
$t/min$ Pressure of system at time $t/mm \ Hg$
$10$ $160$
$\infty$ $240$
Which of the following option is incorrect?

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Reaction $A_{(g)} \rightarrow 2B_{(g)} + C_{(g)}$ is a first order reaction. It was started with pure $A$.$t/min$Pressure of system at time $t/mm \ Hg$$10$$160$$\infty$$240$Which of the following option is incorrect?