Reaction of but-2-ene with acidic KMnO_4 give | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction of but$-2-$ene $(CH_3-CH=CH-CH_3)$ with acidic $KMnO_4$ is an oxidative cleavage reaction.Acidic $KMnO_4$ is a strong oxidizing agent

Vedclass · Accepted Answer

$CH_3COOH$

Vedclass · Answer

(D) The reaction of but$-2-$ene $(CH_3-CH=CH-CH_3)$ with acidic $KMnO_4$ is an oxidative cleavage reaction.Acidic $KMnO_4$ is a strong oxidizing agent that breaks the carbon-carbon double bond.Since but$-2-$ene is a symmetrical alkene,the oxidative cleavage of the double bond results in the formation of two molecules of acetic acid $(CH_3COOH)$.The reaction is: $CH_3-CH=CH-CH_3 + [O] \xrightarrow{KMnO_4/H^+} 2CH_3COOH$.

Reaction of but$-2-$ene with acidic $KMnO_4$ gives:

Similar Questions

The alkene that gives only acetone upon ozonolysis is .......

$A$ dibromide $X$ $(C_4H_8Br_2)$ on dehydrohalogenation gave $Y$,which on reduction with $Z$ gave a non-polar isomer of $C_4H_8$. What are $X$ and $Z$ respectively?

In the reaction given below,the product would be: $CH_3-CH=CH-CH_3 \xrightarrow{H_3O^{+}} CH_3-CH_2-CH(OH)-CH_3$

In alkene (ethene),the number of $sp^2$ hybridized carbon atoms is:

$1-$butylene when subjected to hydroboration-oxidation reaction,yields:

Vedclass Test Series

Exam Paper Generator

Online Exam Module