Reduce the following equation into intercept | vedclass

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Question

(A) The given equation is $3y + 2 = 0$.This can be rewritten as $3y = -2$,or $y = -\frac{2}{3}$.The intercept form of a line is given by $\frac{x}{a}

Vedclass · Accepted Answer

$y$-intercept = $-\frac{2}{3}$,$x$-intercept = does not exist

Vedclass · Answer

(A) The given equation is $3y + 2 = 0$.This can be rewritten as $3y = -2$,or $y = -\frac{2}{3}$.The intercept form of a line is given by $\frac{x}{a} + \frac{y}{b} = 1$,where $a$ is the $x$-intercept and $b$ is the $y$-intercept.Since the equation $y = -\frac{2}{3}$ represents a horizontal line parallel to the $x$-axis,it never intersects the $x$-axis.Thus,the $x$-intercept does not exist,and the $y$-intercept is $-\frac{2}{3}$.

Reduce the following equation into intercept form and find its intercepts on the axes: $3y + 2 = 0$.

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