Reduction of a proper fraction $\frac{f(x)}{g(x)}$ into a sum of partial fractions depends upon the factorization of . . . . . . .

  • A
    $f(x)$ alone
  • B
    $g(x)$ alone
  • C
    both $f(x)$ and $g(x)$
  • D
    factors of $f(x)$ and $g(x)$

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$\begin{aligned} & \text{If } \frac{4x^2+5x^4+7}{(x^2+1)(x^4+x^2+1)} = \frac{Ax+B}{x^2+1} \\ & + \frac{Cx^3+Dx^2+Ex+F}{x^4+x^2+1}, \text{ then } \\ & B+2(D+F+E)-C \cdot A = \end{aligned}$

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