Reduction of aldehydes and ketones to hydrocarbons takes place in the presence of:
- A$Zn$ amalgam and $HCl$ acid
- B$Pd/BaSO_4$
- CAnhydrous $AlCl_3$
- D$Ni/Pt$
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Similar Questions
Assertion : Acetaldehyde on treatment with alkali gives aldol.
Reason : Acetaldehyde molecule contains $\alpha$-hydrogen atom.
Reason : Acetaldehyde molecule contains $\alpha$-hydrogen atom.
MediumAIIMS 1997
View SolutionThe major product of the following reaction is
MediumNEET 2025
View SolutionWhich of the following reactions converts the carbonyl group of aldehydes and ketones to a methylene group on treatment with zinc amalgam and concentrated $HCl$?
Match the following reactions in Column-$1$ with their products in Column-$2$.
Column-$1$ (Reaction) Column-$2$ (Product) $A$. Benzaldehyde + $Zn-Hg/HCl$ $I$. Cyclohexanol $B$. Benzoyl chloride + $H_2/Pd-BaSO_4$ $II$. Benzyl alcohol $C$. Cyclohexanone + $NH_2NH_2/KOH$ $III$. Toluene $IV$. Benzaldehyde $V$. Cyclohexane
The correct match is:
| Column-$1$ (Reaction) | Column-$2$ (Product) |
| $A$. Benzaldehyde + $Zn-Hg/HCl$ | $I$. Cyclohexanol |
| $B$. Benzoyl chloride + $H_2/Pd-BaSO_4$ | $II$. Benzyl alcohol |
| $C$. Cyclohexanone + $NH_2NH_2/KOH$ | $III$. Toluene |
| $IV$. Benzaldehyde | |
| $V$. Cyclohexane |
The correct match is:
DifficultTS EAMCET 2021
View SolutionIdentify product $B$ in the following reaction: $\text{Propanone}$ $\xrightarrow{\text{Ba(OH)}_2} A$ $\xrightarrow{\Delta, -\text{H}_2\text{O}} B$
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