The refractive index of a material is equal to the tangent of the polarising angle. This is called:

$A$ ray of light is incident from a denser to a rarer medium. The critical angle for total internal reflection is $\theta_{iC}$ and Brewster's angle of incidence is $\theta_{iB}$,such that $\sin \theta_{iC} / \sin \theta_{iB} = \eta = 1.28$. The relative refractive index of the two media is

$A$ beam of light strikes a piece of glass at an angle of incidence of $60^{\circ}$ and the reflected beam is completely plane-polarized. The refractive index of glass is

The angle of incidence at which reflected light is totally polarized for reflection from air to glass (refractive index $n$) is:

Can reflection result in plane polarised light if the light is incident on the interface from the side with higher refractive index?

$A$ camera equipped with a polariser is placed on a mountain to record only the reflected image of the sun from the surface of a sea,as shown in the figure. If the sun rises at $6.00 \, AM$ and sets at $6.00 \, PM$ during the summer,then at what time in the afternoon will the recorded image have the lowest intensity? Assume there are no clouds and the intensity of the sun at the sea surface is constant throughout the day. (Refractive index of water $= 1.33$)