Relationship between products (Q) and (S) isC | vedclass

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(D) $1$. The first reaction sequence is hydroboration-oxidation of propene,which follows anti-Markovnikov addition to give propan$-1-$ol $(P)$. Oxidat

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Functional isomer

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(D) $1$. The first reaction sequence is hydroboration-oxidation of propene,which follows anti-Markovnikov addition to give propan$-1-$ol $(P)$. Oxidation of $(P)$ with $PCC$ gives propanal $(Q)$,which is an aldehyde.$2$. The second reaction sequence is oxymercuration-demercuration of propene,which follows Markovnikov addition to give propan$-2-$ol $(R)$. Oxidation of $(R)$ with $PCC$ gives propan$-2-$one $(S)$,which is a ketone.$3$. Both $(Q)$ (propanal) and $(S)$ (propan$-2-$one) have the same molecular formula $C_3H_6O$ but different functional groups (aldehyde vs ketone). Therefore,they are functional isomers.

Relationship between products $(Q)$ and $(S)$ is
$CH_3-CH=CH_2$ $\xrightarrow[H_2O_2, OH^{-}]{BH_3, THF}$ $(P)$ $\xrightarrow[CH_2Cl_2]{PCC}$ $(Q)$
$CH_3-CH=CH_2$ $\xrightarrow[NaBH_4, HO^{-}]{Hg(OAc)_2, H_2O}$ $(R)$ $\xrightarrow[CH_2Cl_2]{PCC}$ $(S)$

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Relationship between products $(Q)$ and $(S)$ is$CH_3-CH=CH_2$ $\xrightarrow[H_2O_2, OH^{-}]{BH_3, THF}$ $(P)$ $\xrightarrow[CH_2Cl_2]{PCC}$ $(Q)$$CH_3-CH=CH_2$ $\xrightarrow[NaBH_4, HO^{-}]{Hg(OAc)_2, H_2O}$ $(R)$ $\xrightarrow[CH_2Cl_2]{PCC}$ $(S)$