Represent the following situation in the form of a quadratic equation:
The product of two consecutive positive integers is $306$. We need to find the integers.
The product of two consecutive positive integers is $306$. We need to find the integers.
(N/A) Let the two consecutive positive integers be $x$ and $x+1$.
According to the problem,the product of these two integers is $306$.
Therefore,$x(x+1) = 306$.
Expanding the equation,we get $x^2 + x = 306$.
Subtracting $306$ from both sides,we obtain the quadratic equation: $x^2 + x - 306 = 0$.
According to the problem,the product of these two integers is $306$.
Therefore,$x(x+1) = 306$.
Expanding the equation,we get $x^2 + x = 306$.
Subtracting $306$ from both sides,we obtain the quadratic equation: $x^2 + x - 306 = 0$.
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