Resistance of a conductivity cell filled with $0.1 \ M$ $KCl$ solution is $100 \ \Omega$ and conductivity of the solution is $1.29 \ S/m$. What will be the value of the cell constant (in $m^{-1}$)?

  • A
    $129$
  • B
    $1.29$
  • C
    $12.9$
  • D
    $0.129$

Explore More

Similar Questions

Which of the following $N$ solutions of $NaCl$ has the maximum specific conductivity?

Match List-$I$ with List-$II$:
List-$I$ (Parameter) List-$II$ (Unit)
$a$. Cell constant $i$. $S\, cm^{2}\, mol^{-1}$
$b$. Molar conductivity $ii$. Dimensionless
$c$. Conductivity $iii$. $m^{-1}$
$d$. Degree of dissociation of electrolyte $iv$. $\Omega^{-1}\, m^{-1}$

Choose the most appropriate answer from the options given below:

The molar conductivities at infinite dilution of barium chloride,sulphuric acid and hydrochloric acid are $280$,$860$ and $426 \, S \, cm^{2} \, mol^{-1}$ respectively. The molar conductivity at infinite dilution of barium sulphate is $...... \, S \, cm^{2} \, mol^{-1}$ ($Round$ off to the Nearest Integer).

$0.01\, S\, m^2\, mol^{-1} = $ ....... $S\, cm^2\, mol^{-1}$

Calculate $\Lambda _{HOAc}^{\infty }$ using appropriate molar conductances of the electrolytes listed below at infinite dilution in $H_2O$ at $25\ ^oC$.
Electrolyte $\Lambda ^{\infty } (S\ cm^2\ mol^{-1})$
$KCl$ $149.9$
$KNO_3$ $145.0$
$HCl$ $426.2$
$NaOAc$ $91.0$
$NaCl$ $126.5$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo