The resistance of a voltameter is 2,Omega. It | vedclass

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(B) According to Faraday's laws of electrolysis,the mass $m$ deposited on the cathode is given by $m = Zit$,where $Z$ is the electrochemical equivalen

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$1.5$

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(B) According to Faraday's laws of electrolysis,the mass $m$ deposited on the cathode is given by $m = Zit$,where $Z$ is the electrochemical equivalent,$i$ is the current through the voltameter,and $t$ is the time.Case $1$: Series connection.The total resistance is $R_s = 2\,\Omega + 3\,\Omega = 5\,\Omega$.The current through the voltameter is $i_1 = \frac{V}{R_s} = \frac{10\,V}{5\,\Omega} = 2\,A$.The mass deposited is $m_1 = Z i_1 t = 1\,g$.Case $2$: Parallel connection.The voltameter is connected directly across the $10\,V$ battery.The current through the voltameter is $i_2 = \frac{V}{R_v} = \frac{10\,V}{2\,\Omega} = 5\,A$.The mass deposited is $m_2 = Z i_2 t$.Taking the ratio: $\frac{m_2}{m_1} = \frac{i_2}{i_1} = \frac{5\,A}{2\,A} = 2.5$.Since $m_1 = 1\,g$,we have $m_2 = 2.5\,g$.The increase in the deposited mass is $\Delta m = m_2 - m_1 = 2.5\,g - 1\,g = 1.5\,g$.

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