Resistivity of 0.5 M electrolytic solution i | vedclass

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(B) $\Lambda_{m}$ is the molar conductivity of the solution.$k$ is the specific conductivity (conductivity) of the solution.$\rho$ is the resistivity

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$200 \ S \ cm^{2} \ mol^{-1}$

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(B) $\Lambda_{m}$ is the molar conductivity of the solution.$k$ is the specific conductivity (conductivity) of the solution.$ho$ is the resistivity of the solution $= 10 \ \Omega \ cm$.$k = \frac{1}{ho} = \frac{1}{10} = 0.1 \ \Omega^{-1} \ cm^{-1} = 0.1 \ S \ cm^{-1}$.Concentration of the solution $c = 0.5 \ M = 0.5 \ mol \ L^{-1}$.The formula for molar conductivity is $\Lambda_{m} = \frac{1000 	imes k}{c}$.Substituting the values: $\Lambda_{m} = \frac{1000 	imes 0.1}{0.5} = \frac{100}{0.5} = 200 \ S \ cm^{2} \ mol^{-1}$.

Resistivity of $0.5 \ M$ electrolytic solution is $10 \ \Omega \ cm$. Find the molar conductivity of the solution.

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