The same mass of CH_4 and H_2 is taken in a c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the mass of both gases be $m \ g$.Number of moles of $CH_4$ $(n_{CH_4})$ = $\frac{m}{16}$.Number of moles of $H_2$ $(n_{H_2})$ = $\frac{m}{2}$

Vedclass · Accepted Answer

$8/9$

Vedclass · Answer

(A) Let the mass of both gases be $m \ g$.Number of moles of $CH_4$ $(n_{CH_4})$ = $\frac{m}{16}$.Number of moles of $H_2$ $(n_{H_2})$ = $\frac{m}{2}$.The partial pressure of a gas is proportional to its mole fraction $(x_i = \frac{n_i}{n_{total}})$.Mole fraction of $H_2$ $(x_{H_2})$ = $\frac{n_{H_2}}{n_{H_2} + n_{CH_4}} = \frac{\frac{m}{2}}{\frac{m}{2} + \frac{m}{16}}$.$x_{H_2} = \frac{\frac{m}{2}}{\frac{8m + m}{16}} = \frac{\frac{m}{2}}{\frac{9m}{16}} = \frac{m}{2} 	imes \frac{16}{9m} = \frac{8}{9}$.Therefore,the partial pressure caused by $H_2$ is $\frac{8}{9}$ of the total pressure.

The same mass of $CH_4$ and $H_2$ is taken in a container. The partial pressure caused by $H_2$ is:

Similar Questions

How many grams of dibasic acid (mol. wt. $200$) should be present in $100 \ mL$ of its aqueous solution to give decinormal strength?

What is the percentage atom economy when the formula weight of the desired product is $65 \text{ u}$ and the sum of the formula weights of all reactants is $130 \text{ u}$ (in $\%$)?

When are the normality $(N)$ and molarity $(M)$ of a solution equal?

Based on the equation $C_6H_{6(l)} + \frac{15}{2} O_{2(g)} \rightarrow 6CO_{2(g)} + 3H_2O_{(l)}$,the enthalpy change is $\Delta H = -3264.4 \, kJ \, mol^{-1}$. How much energy in $kJ$ is released when $7.8 \, g$ of benzene is burned in air?

The density of $SO_2$ at $STP$ is ......... $g/L$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module