The second ionization potential of Li,Be,and | vedclass

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Question

(B) The second ionization potential involves the removal of an electron from the corresponding monovalent cations: $Li^{+}$,$Be^{+}$,and $B^{+}$.The e

Vedclass · Accepted Answer

$Li > B > Be$

Vedclass · Answer

(B) The second ionization potential involves the removal of an electron from the corresponding monovalent cations: $Li^{+}$,$Be^{+}$,and $B^{+}$.The electronic configurations are:$Li^{+} (Z=3): 1s^{2}$$Be^{+} (Z=4): 1s^{2} 2s^{1}$$B^{+} (Z=5): 1s^{2} 2s^{2}$For $Li^{+}$,the electron is removed from the $1s$ orbital,which is very close to the nucleus and highly stable,requiring the highest energy.For $B^{+}$,the electron is removed from the $2s^{2}$ subshell,which is a fully filled stable configuration,requiring more energy than $Be^{+}$.For $Be^{+}$,the electron is removed from the $2s^{1}$ orbital,which is relatively easier as it leads to a stable $1s^{2} 2s^{0}$ configuration.Therefore,the correct order of second ionization potential is $Li > B > Be$.

The second ionization potential of $Li$,$Be$,and $B$ is in the order:

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