See the figure and write the following:
$(i)$ The coordinates of $B$.
$(ii)$ The coordinates of $C$.
$(iii)$ The point identified by the coordinates $(-3, -5)$.
$(iv)$ The point identified by the coordinates $(2, -4)$.
$(v)$ The abscissa of the point $D$.
$(vi)$ The ordinate of the point $H$.
$(vii)$ The coordinates of the point $L$.
$(viii)$ The coordinates of the point $M$.
$(i)$ The coordinates of $B$.
$(ii)$ The coordinates of $C$.
$(iii)$ The point identified by the coordinates $(-3, -5)$.
$(iv)$ The point identified by the coordinates $(2, -4)$.
$(v)$ The abscissa of the point $D$.
$(vi)$ The ordinate of the point $H$.
$(vii)$ The coordinates of the point $L$.
$(viii)$ The coordinates of the point $M$.
(N/A) $(i)$ The $x$-coordinate and the $y$-coordinate of point $B$ are $-5$ and $2$ respectively. Therefore,the coordinates of point $B$ are $(-5, 2)$.
$(ii)$ The $x$-coordinate and the $y$-coordinate of point $C$ are $5$ and $-5$ respectively. Therefore,the coordinates of point $C$ are $(5, -5)$.
$(iii)$ The point whose $x$-coordinate and $y$-coordinate are $-3$ and $-5$ respectively is point $E$.
$(iv)$ The point whose $x$-coordinate and $y$-coordinate are $2$ and $-4$ respectively is point $G$.
$(v)$ The $x$-coordinate of point $D$ is $6$. Therefore,the abscissa of point $D$ is $6$.
$(vi)$ The $y$-coordinate of point $H$ is $-3$. Therefore,the ordinate of point $H$ is $-3$.
$(vii)$ The $x$-coordinate and the $y$-coordinate of point $L$ are $0$ and $5$ respectively. Therefore,the coordinates of point $L$ are $(0, 5)$.
$(viii)$ The $x$-coordinate and the $y$-coordinate of point $M$ are $-3$ and $0$ respectively. Therefore,the coordinates of point $M$ are $(-3, 0)$.
$(ii)$ The $x$-coordinate and the $y$-coordinate of point $C$ are $5$ and $-5$ respectively. Therefore,the coordinates of point $C$ are $(5, -5)$.
$(iii)$ The point whose $x$-coordinate and $y$-coordinate are $-3$ and $-5$ respectively is point $E$.
$(iv)$ The point whose $x$-coordinate and $y$-coordinate are $2$ and $-4$ respectively is point $G$.
$(v)$ The $x$-coordinate of point $D$ is $6$. Therefore,the abscissa of point $D$ is $6$.
$(vi)$ The $y$-coordinate of point $H$ is $-3$. Therefore,the ordinate of point $H$ is $-3$.
$(vii)$ The $x$-coordinate and the $y$-coordinate of point $L$ are $0$ and $5$ respectively. Therefore,the coordinates of point $L$ are $(0, 5)$.
$(viii)$ The $x$-coordinate and the $y$-coordinate of point $M$ are $-3$ and $0$ respectively. Therefore,the coordinates of point $M$ are $(-3, 0)$.
Explore More
Similar Questions
If $(a, b)$ and $(b, a)$ represent the same point in the coordinate plane,then which of the following is possible?
Easy
View Solution$A$ point both of whose coordinates are negative will lie in
Easy
View SolutionIf the point $(a, 0)$ is on the ray $OX^{\prime}$,is $a$ a positive number or a negative number?
Easy
View SolutionAny point on the $y$-axis is of the form
Easy
View SolutionIn which quadrant does a point lie if its $x$-coordinate is negative and the $y$-coordinate is positive?
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo