Seema tried to push a heavy rock of 100 , kg | vedclass

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(A) In physics,work is defined as the product of the force applied and the displacement caused in the direction of the force. The formula for work is

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$0$

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(A) In physics,work is defined as the product of the force applied and the displacement caused in the direction of the force. The formula for work is $W = F 	imes s 	imes \cos(	heta)$,where $W$ is work,$F$ is force,$s$ is displacement,and $	heta$ is the angle between force and displacement.Since the rock did not move,the displacement $(s)$ is $0 \, m$.Therefore,$W = F 	imes 0 = 0 \, J$.Thus,the work done by Seema is $0 \, J$.

Seema tried to push a heavy rock of $100 \, kg$ for $200 \, s$ but could not move it. Find the work done by Seema at the end of $200 \, s$. (in $, J$)

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