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(D) $1$. Acidic strength increases down the group as bond dissociation energy decreases,so $H_2S > H_2O$. Thus,option $A$ is incorrect.$2$. The ${p_\p

Vedclass · Accepted Answer

Bond angle order: $OF_2 < H_2O < Cl_2O < ClO_2$

Vedclass · Answer

(D) $1$. Acidic strength increases down the group as bond dissociation energy decreases,so $H_2S > H_2O$. Thus,option $A$ is incorrect.$2$. The ${p_\pi} - {p_\pi}$ bonding molecular orbital (bonding $M.O.$) formed by the overlap of $p$-orbitals has $\psi$ (gerade) symmetry,while the antibonding $M.O.$ has $\psi$ (ungerade) symmetry. However,the statement in $B$ is often debated based on specific orbital orientation; let's evaluate others.$3$. $NCl_3$ hydrolyzes to form $NH_3$ and $HOCl$ because $Cl$ is more electronegative than $N$. $NF_3$ is resistant to hydrolysis because $N$ is more electronegative than $F$ and there is no vacant $d$-orbital on $N$. Thus,option $C$ is incorrect.$4$. Bond angles: $OF_2$ $(103.2^\circ)$,$H_2O$ $(104.5^\circ)$,$Cl_2O$ $(110.9^\circ)$,$ClO_2$ $(117.4^\circ)$. The order $OF_2 < H_2O < Cl_2O < ClO_2$ is correct due to increasing steric repulsion and electronegativity effects. Therefore,option $D$ is the correct statement.

$(I)$	Dipole moment	$NF_3 > NH_3 > BF_3$
$(II)$	Covalent bond length	$C-O > N-O > O-H$
$(III)$	Bond order	$C_2 > B_2 > He_2$

Select the $CORRECT$ statement.

Similar Questions

Which of the following orders are correct against the property given?
$(I)$ Dipole moment $NF_3 > NH_3 > BF_3$
$(II)$ Covalent bond length $C-O > N-O > O-H$
$(III)$ Bond order $C_2 > B_2 > He_2$

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