Select the incorrect statement.

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(C) $1$. $O_2$ has a bond order of $2$ and $2$ unpaired electrons in its antibonding $\pi^*$ orbitals,making it paramagnetic.$2$. $O_2^+$ has a bond o

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Out of $O_2, O_2^+, O_2^-$,only $O_2$ is paramagnetic.

Vedclass · Answer

(C) $1$. $O_2$ has a bond order of $2$ and $2$ unpaired electrons in its antibonding $\pi^*$ orbitals,making it paramagnetic.$2$. $O_2^+$ has a bond order of $2.5$ and $1$ unpaired electron,making it paramagnetic.$3$. $O_2^-$ has a bond order of $1.5$ and $1$ unpaired electron,making it paramagnetic.$4$. Since $O_2, O_2^+$,and $O_2^-$ all contain unpaired electrons,they are all paramagnetic. Therefore,the statement that 'only $O_2$ is paramagnetic' is incorrect.

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