Select the compound in which chlorine is assi | vedclass

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(C) To find the oxidation number of chlorine $(Cl)$ in each compound,we use the rule that the sum of oxidation numbers in a neutral molecule is $0$. L

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$HClO_3$

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(C) To find the oxidation number of chlorine $(Cl)$ in each compound,we use the rule that the sum of oxidation numbers in a neutral molecule is $0$. Let the oxidation number of $Cl$ be $x$. The oxidation number of $H$ is $+1$ and $O$ is $-2$.For $HClO_3$:$1 + x + 3(-2) = 0$$1 + x - 6 = 0$$x - 5 = 0$$x = +5$.Therefore,in $HClO_3$,the oxidation number of chlorine is $+5$.

Compound	Oxidation number
$1$. $CrO_5$	$a$. $+6$
$2$. $H_2SO_4$	$b$. $+1$
$3$. $C_4OCl_2$	$c$. $-1$
$4$. $(CH_3)_2SO$	$d$. $+2$

Select the compound in which chlorine is assigned the oxidation number $+5$.

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