Select the member$(s)$ of group $14$ that $(i)$ forms the most acidic dioxide,$(ii)$ is commonly found in $+2$ oxidation state,$(iii)$ used as semiconductor.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) $(i)$ Carbon ($CO_2$ is the most acidic dioxide).
$(ii)$ Lead ($Pb$ shows inert pair effect and is stable in $+2$ oxidation state).
$(iii)$ Silicon and Germanium (both are widely used as semiconductors).

Explore More

Similar Questions

Which of the following compounds forms silicones on hydrolysis?

Mention the starting material to produce silicones.

Suggest a reason as to why $CO$ is poisonous.

Difficult
View Solution

$Ge(II)$ compounds are strong reducing agents,whereas $Pb(IV)$ compounds are strong oxidizing agents. This is due to:

An allotrope of carbon which exhibits only two types of $C-C$ bond distances of $143.5 \text{ pm}$ and $138.3 \text{ pm}$, is $....$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo