Select the odd structure out.

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(D) Let us analyze the structure of the given alcohols:$A$: $CH_3-CH(OH)-CH_2-CH_3$ is $butan-2-ol$ (a secondary alcohol with $4$ carbons).$B$: $CH_3-

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$CH_3-CH_2-CH(OH)-C_2H_5$

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(D) Let us analyze the structure of the given alcohols:$A$: $CH_3-CH(OH)-CH_2-CH_3$ is $butan-2-ol$ (a secondary alcohol with $4$ carbons).$B$: $CH_3-CH(OH)-CH_2-CH_2-CH_3$ is $pentan-2-ol$ (a secondary alcohol with $5$ carbons).$C$: $CH_3-CH(OH)-CH_3$ is $propan-2-ol$ (a secondary alcohol with $3$ carbons).$D$: $CH_3-CH_2-CH(OH)-CH_2-CH_3$ is $pentan-3-ol$ (a secondary alcohol with $5$ carbons).All the given structures are secondary alcohols. However,if we look at the symmetry or the chain length,$pentan-3-ol$ $(D)$ is a symmetric secondary alcohol,whereas $A$,$B$,and $C$ are asymmetric secondary alcohols. Alternatively,$B$ and $D$ have $5$ carbons,$A$ has $4$,and $C$ has $3$. The most distinct feature is that $D$ is the only symmetric secondary alcohol where the $-OH$ group is attached to the central carbon of a $5$-carbon chain.

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