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(C) In the reaction of $NaOH$ with $Cl_2$,hydrogen gas $(H_2)$ is not produced. The reaction depends on the concentration of $NaOH$. For cold and dilu

Vedclass · Accepted Answer

$2NaOH + Cl_2 \rightarrow 2NaCl + H_2 + O_2$

Vedclass · Answer

(C) In the reaction of $NaOH$ with $Cl_2$,hydrogen gas $(H_2)$ is not produced. The reaction depends on the concentration of $NaOH$. For cold and dilute $NaOH$,the reaction is: $2NaOH + Cl_2 \rightarrow NaCl + NaClO + H_2O$. For hot and concentrated $NaOH$,the reaction is: $6NaOH + 3Cl_2 \rightarrow 5NaCl + NaClO_3 + 3H_2O$. Option $C$ is incorrect because it suggests the liberation of $H_2$ and $O_2$ gases,which does not occur.

Select the wrong chemical reaction among the following:

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