Seven balls are drawn simultaneously from a bag containing $5$ white and $6$ green balls. The probability of drawing $3$ white and $4$ green balls is:
- A$\frac{7}{{ }^{11}C_7}$
- B$\frac{{ }^5C_3 + { }^6C_4}{{ }^{11}C_7}$
- C$\frac{{ }^5C_3 \times { }^6C_4}{{ }^{11}C_7}$
- D$\frac{{ }^6C_3 \times { }^5C_4}{{ }^{11}C_7}$
Explore More
Similar Questions
An urn contains nine balls of which three are red,four are blue and two are green. Three balls are drawn at random without replacement from the urn. The probability that the three balls have different colours is
$A$ bag contains $6$ white and $4$ black balls. $A$ die is rolled once and the number of balls equal to the number obtained on the die are drawn from the bag at random. The probability that all the balls drawn are white is:
Out of $40$ consecutive natural numbers,two are chosen at random. The probability that the sum of the numbers is odd is:
Easy
View SolutionIn a consignment of $15$ articles,it is found that $3$ are defective. If a sample of $5$ articles is chosen at random from it,then the probability of having $2$ defective articles is
If $6$ boys and $3$ girls are to be seated on $9$ chairs for a photograph,then the probability that the end seats are occupied by the girls and no two girls are side by side is
DifficultMHT CET 2025
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo