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(B) The power rating of each bulb is $P_1 = 10\, W$ at a voltage of $V = 220\, V$.The current drawn by each bulb is $I_1 = \frac{P_1}{V} = \frac{10}{2

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$110$

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(B) The power rating of each bulb is $P_1 = 10\, W$ at a voltage of $V = 220\, V$.The current drawn by each bulb is $I_1 = \frac{P_1}{V} = \frac{10}{220} = \frac{1}{22}\, A$.The maximum allowable current in the circuit is $I_{total} = 5\, A$.Since the bulbs are connected in parallel,the total current is the sum of the currents through each bulb.If $n$ is the number of bulbs,then $I_{total} = n 	imes I_1$.$5 = n 	imes \frac{1}{22}$.$n = 5 	imes 22 = 110$.Therefore,$110$ electric bulbs can be connected in parallel.

Several electric bulbs designed to be used on a $220\, V$ electric supply line,are rated $10\, W$. How many lamps can be connected in parallel with each other across the two wires of a $220\, V$ line if the maximum allowable current is $5\, A$?

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