Show that every positive even integer is of the form $2q$,and that every positive odd integer is of the form $2q+1$,where $q$ is some integer.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Let $a$ be any positive integer and $b=2$. By Euclid's division lemma,for any positive integer $a$ and divisor $b=2$,there exist unique integers $q$ and $r$ such that $a = bq + r$,where $0 \leq r < b$.
Since $b=2$,the possible values for the remainder $r$ are $0$ and $1$ (i.e.,$0 \leq r < 2$).
Case $1$: If $r=0$,then $a = 2q + 0 = 2q$. Since $2q$ is divisible by $2$,$a$ is an even integer.
Case $2$: If $r=1$,then $a = 2q + 1$. Since $2q$ is even,$2q+1$ is not divisible by $2$,so $a$ is an odd integer.
Thus,every positive even integer is of the form $2q$ and every positive odd integer is of the form $2q+1$.

Explore More

Similar Questions

Prove that any positive odd integer is of the form $6m+1$ or $6m+3$ or $6m+5$,where $m \in N \cup \{0\}$.

State whether the following rational number has a terminating decimal expansion or not. If it has,then find it: $\frac{17}{343}$

Show that the cube of any positive integer is of the form $4m, 4m+1$ or $4m+3$ for some integer $m$.

Difficult
View Solution

Use Euclid's division lemma to show that the cube of any positive integer is of the form $9m, 9m+1$ or $9m+8$.

Difficult
View Solution

Every composite number greater than $1$ can be expressed (factorized) as a product of primes,and this factorization is .........,apart from the order in which the prime factors occur.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo