Show the direction of the electric field that arises in a $p-n$ junction.

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(N/A) When a $p-n$ junction is formed,electrons diffuse from the $n$-region to the $p$-region,and holes diffuse from the $p$-region to the $n$-region due to the concentration gradient.
This diffusion leaves behind ionized donor atoms (positive charges) in the $n$-region and ionized acceptor atoms (negative charges) in the $p$-region near the junction.
These immobile charges create an electric field directed from the $n$-region (positive side) to the $p$-region (negative side).
Therefore,the direction of the electric field in the depletion region of a $p-n$ junction is from the $n$-side to the $p$-side.

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In a $p-n$ junction diode, the current $I$ can be expressed as $I=I_{0} \left[\exp \left(\frac{e V}{k_{B} T}\right)-1\right]$, where $I_{0}$ is the reverse saturation current, $V$ is the voltage across the diode (positive for forward bias, negative for reverse bias), $I$ is the current through the diode, $k_{B}$ is the Boltzmann constant $(8.6 \times 10^{-5} \; eV/K)$, and $T$ is the absolute temperature. If for a given diode $I_{0}=5 \times 10^{-12} \; A$ and $T=300 \; K$, then:
$(a)$ What will be the forward current at a forward voltage of $0.6 \; V$?
$(b)$ What will be the increase in the current if the voltage across the diode is increased to $0.7 \; V$?
$(c)$ What is the dynamic resistance?
$(d)$ What will be the current if reverse bias voltage changes from $1 \; V$ to $2 \; V$?

When a $p-n$ junction diode is in forward bias,which type of charge carriers flows in the connecting wire?

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