Shown below are the black body radiation curv | vedclass

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(A) According to Wien's displacement law,the wavelength corresponding to maximum intensity $\lambda_m$ is inversely proportional to the absolute tempe

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(A) According to Wien's displacement law,the wavelength corresponding to maximum intensity $\lambda_m$ is inversely proportional to the absolute temperature $T$,i.e.,$\lambda_m \propto \frac{1}{T}$.Given $T_2 > T_1$,it follows that $\lambda_{m_2} This means the peak of the intensity-wavelength curve for the higher temperature $T_2$ shifts towards a shorter wavelength (left side) compared to the curve for $T_1$.Additionally,according to the Stefan-Boltzmann law,the total energy emitted per unit area per unit time is proportional to $T^4$,so the intensity $I$ for $T_2$ will be higher than for $T_1$ at all wavelengths.Therefore,the correct plot is the one where the curve for $T_2$ is higher and its peak is shifted to the left relative to the curve for $T_1$.

Shown below are the black body radiation curves at temperatures $T_1$ and $T_2$ $(T_2 > T_1)$. Which of the following plots is correct?

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