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In an ammeter,$0.25 \%$ of the main current passes through the galvanometer. If the resistance of the galvanometer is $G$,the resistance of the ammeter will be:

Match the terms given in List-$I$ with suitable options provided in List-$II$ regarding the experiment to calculate the resistance and figure of merit of a galvanometer using the half-deflection method:
List-$I$ List-$II$
$A$. Figure of merit $(k)$ $P$. in series
$B$. Current sensitivity $(SI)$ $Q$. to get power loss minimized
$C$. Deflection is made half by using low resistance $R$. in shunt/parallel
$D$. High resistance box $S$. current per unit deflection
$T$. deflection per unit current

$A$ moving coil galvanometer has a resistance of $50\,\Omega$ and gives full-scale deflection for $10\,mA$. How could it be converted into an ammeter with a full-scale deflection for $1\,A$?

$A$ moving coil galvanometer of resistance $100 \,\Omega$ is used as an ammeter using a shunt resistance of $0.1 \,\Omega$. The maximum deflection current in the galvanometer is $100 \,\mu A$. Find the minimum current in the circuit so that the ammeter shows maximum deflection in $mA$.

$A$ teacher in his physics laboratory allotted an experiment to determine the resistance $(G)$ of a galvanometer. Students took the observations for $\frac{1}{3}$ deflection in the galvanometer. Which of the following is true for measuring the value of $G$?

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