Silver chloride dissolves in excess of ammonium hydroxide solution. The cation present in the resulting solution is

  • A
    $[Ag(NH_3)_6]^+$
  • B
    $[Ag(NH_3)_4]^+$
  • C
    $Ag^+$
  • D
    $[Ag(NH_3)_2]^+$

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The molecular formula of a cobalt coordination complex contains five ammonia molecules,one nitro group,and two chlorine atoms for one cobalt atom. In an aqueous solution,one mole of the substance produces $3$ moles of ions. Upon reacting this solution with an excess of silver nitrate solution,$2$ moles of $AgCl$ precipitate are obtained. What is the ionic formula of the complex?

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The solubility of $AgCl$ in $NH_4OH$ is due to the formation of:

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When $0.1 \ mole$ of $CoCl_3(NH_3)_5$ is treated with excess of $AgNO_3$,$0.2 \ mole$ of $AgCl$ are obtained. The conductivity of the solution will correspond to:

Assertion : Low spin complexes have lesser number of unpaired electrons.
Reason : $[FeF_6]^{3-}$ is a low spin complex.

Which among the following cations forms a least stable complex if the ligand is same?

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