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(B) The number of equivalents of $AgNO_3$ present is $N 	imes V(L) = 0.1 	imes 0.2 = 0.02 \ 	ext{equivalents}$.We need to remove half of the silver

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$9650$

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(B) The number of equivalents of $AgNO_3$ present is $N 	imes V(L) = 0.1 	imes 0.2 = 0.02 \ 	ext{equivalents}$.We need to remove half of the silver,which is $0.02 / 2 = 0.01 \ 	ext{equivalents}$.According to Faraday's law,the number of equivalents deposited is given by $W = \frac{I 	imes t}{96500}$.Substituting the values: $0.01 = \frac{0.1 	imes t}{96500}$.Solving for $t$: $t = 0.01 	imes 96500 / 0.1 = 9650 \ 	ext{seconds}$.

Silver is removed electrically from $200 \ mL$ of a $0.1 \ N$ solution of $AgNO_3$ by a current of $0.1 \ A$. How long will it take to remove half of the silver from the solution? $(F = 96500 \ C \ mol^{-1})$

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