Six-elevenths of a number is equal to 22 % of | vedclass

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(D) Given,the third number $= 2400$.The second number $= \frac{1}{4} 	imes 2400 = 600$.Let the first number be $x$. According to the problem,$\frac{6

Vedclass · Accepted Answer

$108.9$

Vedclass · Answer

(D) Given,the third number $= 2400$.The second number $= \frac{1}{4} 	imes 2400 = 600$.Let the first number be $x$. According to the problem,$\frac{6}{11}x = 22 \%$ of $600$.$\frac{6}{11}x = \frac{22}{100} 	imes 600$.$\frac{6}{11}x = 22 	imes 6 = 132$.$x = 132 	imes \frac{11}{6} = 22 	imes 11 = 242$.Now,we need to find $45 \%$ of the first number $(242)$:$45 \% 	ext{ of } 242 = \frac{45}{100} 	imes 242 = 0.45 	imes 242 = 108.9$.

Six-elevenths of a number is equal to $22 \%$ of a second number. The second number is equal to one-fourth of a third number. The value of the third number is $2400$. What is $45 \%$ of the first number?

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