Six equal resistances are connected between p | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let each resistance be $r$. The circuit consists of three branches between the nodes $P, Q,$ and $R$.Branch $PQ$ has one resistance $r$.Branch $QR

Vedclass · Accepted Answer

$P$ and $Q$

Vedclass · Answer

(B) Let each resistance be $r$. The circuit consists of three branches between the nodes $P, Q,$ and $R$.Branch $PQ$ has one resistance $r$.Branch $QR$ has two resistances in parallel,so its equivalent resistance is $r_{QR} = r/2$.Branch $PR$ has two resistances in parallel,so its equivalent resistance is $r_{PR} = r/2$.$1$. Resistance between $P$ and $Q$ $(R_{PQ})$:$R_{PQ}$ is the parallel combination of the branch $PQ$ (resistance $r$) and the series combination of branches $PR$ and $QR$ (resistance $r/2 + r/2 = r$).$R_{PQ} = \frac{r 	imes r}{r + r} = \frac{r}{2} = 0.5r$.$2$. Resistance between $Q$ and $R$ $(R_{QR})$:$R_{QR}$ is the parallel combination of the branch $QR$ (resistance $r/2$) and the series combination of branches $PQ$ and $PR$ (resistance $r + r/2 = 1.5r$).$R_{QR} = \frac{(r/2) 	imes (1.5r)}{(r/2) + (1.5r)} = \frac{0.75r^2}{2r} = 0.375r$.$3$. Resistance between $P$ and $R$ $(R_{PR})$:$R_{PR}$ is the parallel combination of the branch $PR$ (resistance $r/2$) and the series combination of branches $PQ$ and $QR$ (resistance $r + r/2 = 1.5r$).$R_{PR} = \frac{(r/2) 	imes (1.5r)}{(r/2) + (1.5r)} = 0.375r$.Comparing the values: $R_{PQ} = 0.5r$,$R_{QR} = 0.375r$,and $R_{PR} = 0.375r$.Thus,the net resistance is maximum between $P$ and $Q$.

Six equal resistances are connected between points $P, Q$ and $R$ as shown in the figure. Then the net resistance will be maximum between:

Similar Questions

Two heater wires of equal length are first connected in series and then in parallel. The ratio of heat produced in the two cases is

The resistance across $M$ and $N$ in the given figure is

$6 \Omega$ and $12 \Omega$ resistors are connected in parallel. This combination is connected in series with a $10 \text{ V}$ battery and a $6 \Omega$ resistor. What is the potential difference between the terminals of the $12 \Omega$ resistor (in $\text{ V}$)?

The equivalent resistance between the points $P$ and $Q$ in the network given here is equal to ................ $\Omega$ (given $r = \frac{3}{2} \Omega$).

In the given circuit,the value of $I_{2}$ is: (in $A$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module