Sodium ethoxide reacts with ethanoyl chloride. The compound that is produced in the above reaction is:

The major product formed in the following reaction is
$C_6H_5CH=CH_2$ $\xrightarrow[(ii) H_3O^+]{(i) KMnO_4, KOH, \Delta}$ $\xrightarrow{(iii) Br_2/FeBr_3} \text{Product}$

Two statements are given below:
Statement $I:$ The melting point of monocarboxylic acids with an even number of carbon atoms is higher than that of acids with an odd number of carbon atoms immediately below and above it in the series.
Statement $II:$ The solubility of monocarboxylic acids in water decreases with an increase in molar mass.
Choose the most appropriate option.

The compound, which evolves carbon dioxide on treatment with an aqueous solution of sodium bicarbonate at $25^{\circ} C$, is

$CH_3CH(I)_2$ $\xrightarrow{KCN}$ $\xrightarrow[\Delta]{H_3O^{+}} ?$ Here the end product would be

The common acid used in the manufacture of rayon and plastics is