Sodium generally does not show an oxidation s | vedclass

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Question

(B) The electronic configuration of $Na$ is $[Ne] 3s^1$. After the removal of one electron,it achieves the stable noble gas configuration of $Ne$ $(1s

Vedclass · Accepted Answer

High second ionization potential

Vedclass · Answer

(B) The electronic configuration of $Na$ is $[Ne] 3s^1$. After the removal of one electron,it achieves the stable noble gas configuration of $Ne$ $(1s^2 2s^2 2p^6)$. Removing a second electron requires a very high amount of energy because it involves breaking the stable octet configuration of the $Ne$ core. Therefore,the second ionization potential of $Na$ is extremely high,making the $+2$ oxidation state energetically unfavorable. Thus,$B$ is the correct option.

Sodium generally does not show an oxidation state of $+2$,because of its

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