Sodium has a body-centered cubic (BCC) packin | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a body-centered cubic $(BCC)$ structure,the nearest neighbor distance $d$ is given by the distance between the corner atom and the body-center

Vedclass · Accepted Answer

$4.3$

Vedclass · Answer

(B) For a body-centered cubic $(BCC)$ structure,the nearest neighbor distance $d$ is given by the distance between the corner atom and the body-centered atom.In a $BCC$ unit cell with lattice parameter $a$,the body diagonal is $\sqrt{3}a$.The distance between the nearest atoms is $d = \frac{\sqrt{3}a}{2}$.Given $d = 3.7 \mathring{A}$,we can solve for $a$:$a = \frac{2d}{\sqrt{3}} = \frac{2 	imes 3.7}{1.732} \approx 4.27 \mathring{A}$.Rounding to one decimal place,we get $a = 4.3 \mathring{A}$.

Sodium has a body-centered cubic $(BCC)$ packing. If the distance between two nearest atoms is $3.7 \mathring{A}$,then its lattice parameter is.....$\mathring{A}$

Similar Questions

For a crystal system where $a = b = c$ and $\alpha = \beta = \gamma \neq 90^\circ$,the system is:

At ordinary temperatures, the electrical conductivity of semiconductors in $S/m$ (or $mho/m$) is in the range:

The resistivity $(\rho)$ of a semiconductor varies with temperature. Which of the following curves represents the correct behavior?

Which of the following statements is true?

What is an energy band?

Vedclass Test Series

Exam Paper Generator

Online Exam Module