Sodium sulphite on heating with dilute HCl li | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) When sodium sulphite $(Na_2SO_3)$ reacts with dilute $HCl$,it liberates sulphur dioxide $(SO_2)$ gas: $Na_2SO_3 + 2HCl 	o 2NaCl + H_2O + SO_2 \up

Vedclass · Accepted Answer

Turns acidified potassium dichromate paper green

Vedclass · Answer

(B) When sodium sulphite $(Na_2SO_3)$ reacts with dilute $HCl$,it liberates sulphur dioxide $(SO_2)$ gas: $Na_2SO_3 + 2HCl 	o 2NaCl + H_2O + SO_2 \uparrow$ $SO_2$ gas acts as a reducing agent and reduces acidified potassium dichromate $(K_2Cr_2O_7)$ to chromium sulphate $(Cr_2(SO_4)_3)$,which is green in color: $K_2Cr_2O_7 + 3SO_2 + H_2SO_4 	o K_2SO_4 + Cr_2(SO_4)_3 	ext{ (green)} + H_2O$ Therefore,the gas turns acidified potassium dichromate paper green.

Sodium sulphite on heating with dilute $HCl$ liberates a gas which

Similar Questions

An anion solution gives a white precipitate with $AgNO_3$ solution. The precipitate dissolves in dilute ammonia due to the formation of:

When a few drops of $KMnO_4$ are added to an acidic solution of an anion,which of the following,if present,will $NOT$ decolorize $KMnO_4$?

$A$ salt gives violet vapours when treated with conc. $H_2SO_4$. It contains

$A$ sodium salt on treatment with $MgCl_2$ gives white precipitate only on heating. The anion of the sodium salt is

Which reagent is used to remove $SO_4^{2-}$ and $Cl^{-}$ ions from a solution?

Vedclass Test Series

Exam Paper Generator

Online Exam Module