Solid targets of different elements are bombarded by highly energetic electron beams. The frequency $(f)$ of the characteristic $X-$rays emitted from different targets varies with atomic number $Z$ as

An electron having de-Broglie wavelength $\lambda$ is incident on a target in an $X$-ray tube. The cut-off wavelength of the emitted $X$-ray is:

The $K_{\alpha}$ $X$-ray of molybdenum has a wavelength of $0.071 \, nm$. If the energy of a molybdenum atom with a $K$ electron knocked out is $27.5 \, keV$,the energy of this atom when an $L$ electron is knocked out will be $.... \, keV$. (Round off to the nearest integer) $[h = 4.14 \times 10^{-15} \, eVs, c = 3 \times 10^{8} \, ms^{-1}]$

The shortest wavelength of $X-$rays emitted from an $X-$ray tube depends upon

The $K_{\alpha}$ wavelength emitted by an atom of atomic number $Z = 11$ is $\lambda$. Find the atomic number for an atom that emits $K_{\alpha}$ radiation with wavelength $4\lambda$.

The wavelength of $X$-rays is of the order of ...... $ \mathring A $.