Solubility product of CaC_2O_4 at a given tem | vedclass

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(A) Given,$K_{sp} = 4 	imes 10^{-9} \ (mol \ L^{-1})^2$. For the dissociation of $CaC_2O_4$: $CaC_2O_4(s) ightleftharpoons Ca^{2+}(aq) + C_2O_4^{2-

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$6.3 	imes 10^{-5} \ mol \ L^{-1}$

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(A) Given,$K_{sp} = 4 	imes 10^{-9} \ (mol \ L^{-1})^2$. For the dissociation of $CaC_2O_4$: $CaC_2O_4(s) ightleftharpoons Ca^{2+}(aq) + C_2O_4^{2-}(aq)$. Let the solubility be $S \ mol \ L^{-1}$. Then,$[Ca^{2+}] = S$ and $[C_2O_4^{2-}] = S$. $K_{sp} = [Ca^{2+}][C_2O_4^{2-}] = S 	imes S = S^2$. $S^2 = 4 	imes 10^{-9}$. $S = \sqrt{4 	imes 10^{-9}} = \sqrt{40 	imes 10^{-10}} = 6.32 	imes 10^{-5} \ mol \ L^{-1}$. Thus,the solubility of $CaC_2O_4$ is $6.3 	imes 10^{-5} \ mol \ L^{-1}$.

Solubility product of $CaC_2O_4$ at a given temperature in pure water is $4 \times 10^{-9} \ (mol \ L^{-1})^2$. Solubility of $CaC_2O_4$ at the same temperature is

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