Solubility product of a salt AB is 1 times 10 | vedclass

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(C) The dissociation of the salt is given by: $AB \rightleftharpoons A^{+} + B^{-}$The solubility product expression is: $K_{sp} = [A^{+}][B^{-}]$Prec

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$> 10^{-5} \ M$

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(C) The dissociation of the salt is given by: $AB ightleftharpoons A^{+} + B^{-}$The solubility product expression is: $K_{sp} = [A^{+}][B^{-}]$Precipitation occurs when the ionic product exceeds the solubility product: $[A^{+}][B^{-}] > K_{sp}$Given $[A^{+}] = 10^{-3} \ M$ and $K_{sp} = 1 	imes 10^{-8}$,we substitute these values:$(10^{-3})[B^{-}] > 1 	imes 10^{-8}$$[B^{-}] > \frac{1 	imes 10^{-8}}{10^{-3}}$$[B^{-}] > 1 	imes 10^{-5} \ M$

Solubility product of a salt $AB$ is $1 \times 10^{-8}$ in a solution in which the concentration of $A^{+}$ ions is $10^{-3} \ M$. The salt will precipitate when the concentration of $B^{-}$ ions is kept

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